in ideal solution of non volatile solute B and solvent Ain 2 :5 molar ratio has vapour pressure 250 mm. if a another solution in ratio 3:4 prepared then vapour pressure above this solution 1) 200 mm 2) 250 mm 3) 350 mm 4) 400 mm
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molar ratio of solute and solvent is 2:5
so mole fraction of solvent,×∧=5/2+5=0.71
using Raoult's law:
p(solution)×mole fraction of solvent
250=p(pure solvent)×0.71
p(pure solvent)=352.11mm
molar ration of solute and solvent is 3:4
so mole fraction of solvent,×∧=4/3+4=0.57
p(solution)=352.11×0.57=200.7mm
therefore, the correct option is 1)200mm
so mole fraction of solvent,×∧=5/2+5=0.71
using Raoult's law:
p(solution)×mole fraction of solvent
250=p(pure solvent)×0.71
p(pure solvent)=352.11mm
molar ration of solute and solvent is 3:4
so mole fraction of solvent,×∧=4/3+4=0.57
p(solution)=352.11×0.57=200.7mm
therefore, the correct option is 1)200mm
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