Question

In ∆, if ∠ = 1000 , PM bisects ∠ and PM⊥QR then find ∠.​

Answer 1

Answer:

∠QPR=80°

∠PQR+∠QPR+∠QRP=180°

∠PQR+∠QRP=100°

2(x+y)=100°

x+y=50°

So, in △QOR

x+y+∠QOR=180°

∴∠QOR=180°−50°

=130°