Question

in) if A-31-4j+2k and B= -2- +3k find out AxB and A.B and also calculate
the angle between these two vectors.
​

Answer 1

Explanation:

we can do it in two ways either by doing

cross product or dot product

FIRST BY USING DOT PRODUCT

_ _

A.B=ABcos(tita)------(1)

_ _

find A.B=(3i-4j+2k).(-2i+3k)=-6+6=0

_ _

now find magnitude of |a| and |b|

_

|A| =√3²+4²+2²=√29

_

|B| =√2²+3²=√13

now from (1)

A.B=ABcos(tita)

0=ABcos(tita)

cos(tita)=0

tita=90°