Question

in image plese solve it ​

Answer 1

Answer:

$\pink{area \: of \: circle = \pi {r}^{2}}$

dimeter of inner circle = 4 then radius = 2

$\frac{22}{7} \times 2 \times 2 = \frac{352}{7}$

$\frac{325}{21} = area \: of \: inner \: circle$

DIMETER OF OUTER CIRCLE =10

SO RADIUS = 5

AREA =

$\frac{22}{7} \times 5 \times 5 = \frac{550}{7}$

$\frac{550}{7} = area \: of \: bigger \: circle$

substract area of outer circle ⭕ to area of iner circle

area of shaded portion = area of big circle - area of small circle

$\frac{550}{7} - \frac{352}{7}$

$\frac{550 - 352}{7}$

$\frac{198}{7} = shaded \: portion$

499.71 in point

Answer 2

Answer:

The area of the shaded region $=21\pi$ $cm^{2}$

Step-by-step explanation:

There is a big circle of diameter $10cm$, hence its radius $=5cm$

and there is a small circle of diameter $4cm$, hence its radius $=2cm$.

Now, area of the shaded region $=$ area of big circle $-$ area of small circle.

Area of big circle      

           $=\pi r^{2} =\pi (5^{2} )=25\pi\ cm^{2}$.

Area of small circle

          $=\pi r^{2} =\pi (2^{2} )=4\pi\ cm^{2}$

Hence the area of the shaded region  $=25\pi -4\pi =21\pi\ cm^{2}$

Hence the answer

thank you