Question

In in a right angle triangle pqr right angled at Q if PQ is equal to 8 cm and PR is equal to 10 cm find QR

Answer 1

Answer:

Given: PQ=10cm, PR=24cm

Let QR be x cm.

In right angled triangle QPR,

(Hypotenuse)2=(Base)2+(Perpendicular)2 [By Pythagoras theorem]

⇒(QR)2=(PQ)2+(PR)2

⇒x2=(10)2+(24)2

⇒x2=100+576=676

⇒x=676=26cm

Thus, the length of QR is 26cm.