Question

In, in an angle abc,ab=ac and angle abc=43 find angle ABC and angle bac

Answer 1

Answer:

i hope the figure attached is the one you described.

Sorry for the sloppy figure

In Figure

AB=AC

∠ABC=42

∠ABC=∠ACB           (Isosceles Triangle Theorem)  --(1)

Hence ∠ACB=42

We Know sum of all 3 angles of a Triangle is 180

=> ∠ABC+∠ACB+∠BAC=180

from equation 1

=> ∠ABC+∠ABc+∠BAC=180

=>84+∠BAC=180

=>∠BAC=180-84 = 96

Hence ∠BAC= 96

Answer 2

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In figure ∆ACB

AB = AC

∆ABC = 43

∆ABC = ∆ACB (Isoceles ∆)

Theorem 1st

ACB = 43

To Find :-

BAC = x

We know sum of three angles are 180°

→ ABC + ACB + BAC = 180

→ 43 + 43 + x = 180°

→ 86 + x = 180

→ x = 180 - 86

→ x = 94

Hence,

∆BAC = 94