Question

In
in
hydrogen
atom
absorbs
1.50
times
of
its
ionization
energy
The
velocity
emitted electron will be
1) 1.55 x 100 m/s
2) 1.55 x 100 cm/s
3) 1.55 x 100 km/s
4) 1.55 x 100 cm​

Answer 1

Answer:

v hfh kh

Explanation:

nvxktdxjgdgk you want it to the cycle aagya

Answer 2

Answer:

Energy absorbed =13.6×1.5=20.4eV.

Of this 6.8eV is converted to K.E. as I.E. is 13.6 eV

6.8eV⇒6.8×1.6×10

−19

J;

6.8×1.6×10

−19

=K.E=(

2

1

)mv

2

v=

m

2KE

=

9.1×10

−31

2×1.088×10

−18

v=1.54×10

6

m/s

Explanation:

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