Question

in) in parallelogram ABCD, AB=4cm., BC=6cm. and ABC = 30°, find the area of
field in the shape of parallelogram ABCD.

The answer is 12 plz give me a step by step explanation answer... ​

Answer 1

Answer:

Step-by-step explanation:

draw a perpendicular CE from C to side AB

since angle ABC=30 Degree

CE=sin 30*6=3 cm

area of parallelogram= base * height=3*4=12 sq Cm