in) in parallelogram ABCD, AB=4cm., BC=6cm. and ABC = 30°, find the area of
field in the shape of parallelogram ABCD.
The answer is 12 plz give me a step by step explanation answer...
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Answer:
Step-by-step explanation:
draw a perpendicular CE from C to side AB
since angle ABC=30 Degree
CE=sin 30*6=3 cm
area of parallelogram= base * height=3*4=12 sq Cm
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