in in the given figure ,angle ABC is equal to 60 degree, angle BCE is equal to 25 degree ,angle DCE is equal to 35 degree and angle CEF is equal to 145,then find the relation between AB and EF.
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Given: y = 45 and AB||CE
When a transversal intersects two parallel lines (as shown below), we get several equal angles.
So we also know that ∠ECD = x° .
We get the following
Image
Also given: CE = DE
When we add this information to our diagram, we see that ∆ECD is an isosceles triangle, which means ∠CDE = x°
Image
Since angles in a triangle add to 180°, we can write: 45 + x + x = 180
Simplify: 45 + 2x = 180
Subtract 45 from both sides: 2x = 135
Divide both sides by 2 to get: x = 67.5
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