Question

in in the given figure triangle ABC is an isosceles triangle inscribed in a circle with centre o if AB = AC prove that AP bisects BPC​

Answer 1

Step-by-step explanation:

∆AOB≈∆AOC, by RHS criterion.

thus, BO=CO.

∆PCO≈∆PBO.

THUS, AP bisects BPC...

This is the solution...