Question

In in triangle ABC angle

B 45 degree c equal to 55 degree ab bisects angle a find angle ADB and angle ADC ​

Answer 1

here is your answer-

<B=45°

<C=55°

In ∆ABC,

<B+<C+<A=180°

(triangle sum property)

45+55+<A=180°

100+<A=180°

<A=180°-100°

<A=80°

AD bisect angle A

<BAD=<CAD=<A/2=40°

In ∆ABD,

<BAD+<B+<ADB=180°

40°+45°+<ADB=180°

85°+<ADB=180°

<ADB=180°-85°

<ADB=95°

similarly, In ∆ ACD

<ADC=85°

I hope this will help you.