Question

In in triangle abc, de l l bc, D on AB and E on AC, if AD/DB equal to 3/4 find BC/DE​

Answer 1

Answer:

△ABC, we have

       DE∣∣BC

⇒ ADAB=AEAC

Thus, in triangles ABC and ADE, we have

        ADAB=AEAC

and, ∠A=∠A

Therefore, by SAS-criterion of similarity, we have

      △ABC∼△ADE

⇒ ADAB=DEBC.......(i)

It is given that 

    ADAB=32

⇒ ADDB=23

⇒  ADDB+1=23+1

⇒ ADDB+AD=25

⇒  ADAB=25   .............(ii)

From (i) and (ii), we get