in in triangle abc if ab is twice of BC then the correct statement is
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Given : a right angle triangle ABC , AB is twice of BC
To Find : Correct Statement
AC² = AB² + 2BC²
AC² = 3BC²
AC² = 5BC²
AC² = 5AB²
Solution:
Using Pythagoras theorem :
AC² = AB² + BC²
AB = 2BC
=> AC² = (2BC)² + BC²
=> AC² = 4BC² + BC²
=> AC² = 5BC²
AC² = 5BC² is correct option
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