Question

in increasing list of consecutive positive integers, the 3th and 4th numbers in the list add to 11. What is the 6th number in the list?

Answer 1

Answer:

in 6 number list I thin no one can there May be I wrong

Answer 2

Given:

in an increasing list of consecutive positive integers, the 3rd and 4th numbers in the list add to 11.

To Find:

What is the 6th number on the list?

Solution:

If it is a list of consecutive positive integers then we can consider it as an AP with a common difference of 1 and let the first term be 'a'

Now the 3rd term will be,

$T_{3}=a+2$

And the 4th term will be,

$T_{4}=a+3$

Now it is given that the sum of these terms is equal to 11, putting it in the equation we have,

$11=a+2+a+3\\11=2a+5\\2a=6\\a=3$

So the first term is 3, now calculating the 6th term,

$T_{6}=a+(n-1)d\\=3+5\\=8$

Hence, the 6th number in the list is 8.