In interference, two individual amplitudes are 5 units and 3 units. Find (a)A_(max)/A_(min) (b) I_(max)/I_(min) .
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Answered by
3
Answer:
A_(max) = 8 units
A_(min) = 2 units
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Answered by
0
Answer:
Intensities are 9 and 4 units
Amplitudes are 3 and 2 respectively.
At maxima amplitudes add up giving 5 units.
At minima amplitudes substract giving -1 units.
The ratio of Intensities of maxima and minima is given by 25/1
Explanation:
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