Question

In ∆ is a right angled at R .If PR =5 cm and QR= 12cm,find the

length of PQ?​

Answer 1

Step-by-step explanation:

in a right angle

PQ ^2 = P R ^2 + Q R ^2

PQ^2=(5)^2 + (12)^2

PQ= 13cm

Answer 2

• PQ is of 13 cm

Step-by-step explanation:

Given:-

• A triangle is right angled at R.
• PR is 5 cm.
• QR is 12 cm.

To find:-

• Length of PQ .

Solution:-

• If one side of any right angled triangle is not given. Then we use Pythagoras theorem. So,

By using Pythagoras theorem that is :-

Hypotenuse² = Base² + Perpendicular²

So,

Hypotenuse = PQ = ?

Base = QR = 12 cm

Perpendicular = PR = 5 cm

Put the values in Pythagoras theorem

➞ PQ² = (12)² + (5)²

➞ PQ² = 144 + 25

➞ PQ² = 169

➞ PQ = √169

➞ PQ = 13

Therefore,

Length of PQ is 13 cm.