In isoceles triangle ABC b=90 then find 2 sinacosa
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Hey mate ...
The sum of all angles are 180°
Given that < B is 90°
therefore, <A+ <C = 180°-90° = 90°
as the pair of angles opposit to equal sides of isosceles triangle are equal..
<B = 90/2 = 45° ...
<C = 45°
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