In isolation (triangle) ABC, AB=AC=8cm and BC=6cm. If the length of altitude on base is 5cm. find the length of altitude on equal side of triangle.
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Answer:
13 cm. applying Pythagoras Theorem, we get
AB = sqrt((AC)^2 + (BC)^2)
or, AB = sqrt(5^2 + 12^2)
or, AB = sqrt(25+144)
or, AB = sqrt(169)
so, AB = 13 cm. :)
Step-by-step explanation:
nikks72:
ans of this question is H1= 3.75 cm H2 =3.75 cm
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