Question

in isosceles right angled triangle abc right angle at a , bc =10 cm , bisector of angle c meets ab at d find ad​

Answer 1

Answer:

let ab=x

so x^2+x^2= 10^2 by pythagoras

or x=√50

so ab=ac=√50

Now as Ad is bisector of anle A by basic proportionality theorem

CA/CB= AD/BD

or √50/10=AD/(√50-AD)

or AD = 50/(10+√50)=5(2-√2)