in isosceles triangle ABC,AB=AC.the side BA is produced to D such that BA=AD.prove that:angleBCD=90degree
Answers
Answered by
2
since
ab=ac=ad
then
angB=angACB=angACD=angD=X
WE KNOW THAT IN TRIANGLE PBC
X+2X+X=180
4X=180
X=45
THEREFORE
angc=x+x=2x=x*45=90
hence proved
ab=ac=ad
then
angB=angACB=angACD=angD=X
WE KNOW THAT IN TRIANGLE PBC
X+2X+X=180
4X=180
X=45
THEREFORE
angc=x+x=2x=x*45=90
hence proved
Answered by
0
Given
ab=ac=ad
AngleB=angleACB=angleACD=angleD=X
In triangle PBC
X+2X+X=180
4X=180
X=45
Therfore
angleC=X+X=2x=x*45=90
Proved
Similar questions
Computer Science,
8 months ago
Math,
8 months ago
Hindi,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago