in isosceles triangle if ab=ac=25 and bc=14.then what is the measure of altitude from a on bc
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Answered by
1
heyy...
by pathagoras theorem..
ac2 = bc2 + ad2
25^2 = 7^2 + ad2
625 = 49 + ad2
ad2 = 625 - 49
ad = under root 576
ad = 24
24 will be the length of ad , the altitude
hope it helps u...thanks...!!!
by pathagoras theorem..
ac2 = bc2 + ad2
25^2 = 7^2 + ad2
625 = 49 + ad2
ad2 = 625 - 49
ad = under root 576
ad = 24
24 will be the length of ad , the altitude
hope it helps u...thanks...!!!
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Answered by
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IN TRIANGLE ABC IF ALTITUDE FROM A IS DRAWN TO BC. THEN IN THE ISOSCELES TRIANGLE MEDIAN AND ALTITUDE COINCIDE.
THEREFORE D IS A POINT ON BC .BD=CD=7.
ACCORDING TO PYTHAGORAS THEROM,
AB^2=AD^2+BD^2
25×25= AD^2 +7×7
625=AD^2+49
625-49=AD^2
576=AD^2
AD=24.
AREA OF ABC= 1/2×14×24
= 168sq unit
HOPE THIS HELPS U
THEREFORE D IS A POINT ON BC .BD=CD=7.
ACCORDING TO PYTHAGORAS THEROM,
AB^2=AD^2+BD^2
25×25= AD^2 +7×7
625=AD^2+49
625-49=AD^2
576=AD^2
AD=24.
AREA OF ABC= 1/2×14×24
= 168sq unit
HOPE THIS HELPS U
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palak k
hu
gud9
Similar questions
=24
Let the radius be x
=> OD 24 - x
x2−(24−x)2=72x−)=7
=>x2−x2−576+48x=49=>x−x−
=>48x=625=>
=>x=62548