Question

in it for an Ap., t₂ = 4 and d=-2, then what
is the value of a ?​

Answer 1

Answer:

$t_{n} = a + (n - 1) \times d \\ t_{2} = a + (2 - 1) \times - 2 \\ 4 = a + 1 \times - 2 \\ 4 = a - 2 \\ a = 4 + 2 \\ a = 6$

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