In January 1990 a man's salary was 2250 p.a .if his annual increment is 108 ,find what was his salary in 1996
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Solution:
Given- The man's salary in the year 1990 = 2250 p.a.
The man's annual increment = 108
To find- The man's salary in the year 1996 (ie. after 6 years) = ?
The man's salary in the year 1996 = The man's current salary + Increment × 6 yrs
=2250+108×6
=3,330
Therefore, the man's salary in the year 1996 is Rs. 3,330 p.a.
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