In △jkl, solve for x.triangle jkl where angle k is a right angle. kl measures 34. jk measures x. angle j measures 27 degrees.
Answers
Answered by
22
From the attached diagram;
JK = x = Adjacent
KL = 34 = Opposite
JL = Hypotenuse
Since we have opposite and we need adjacent, we will use Tan
Tan 27 = 34/x
x = 34/Tan 27
x = 66.73
JK = x = Adjacent
KL = 34 = Opposite
JL = Hypotenuse
Since we have opposite and we need adjacent, we will use Tan
Tan 27 = 34/x
x = 34/Tan 27
x = 66.73
Attachments:
Similar questions