In June 2012, the average daily temperature was higher than 39°C for 28 days. What was the percentage of the days for which the average daily temperature was below 39°C?
Answers
Answer:
Total 7 days average is 30 so Total Temperature is 7*30=210
First 3 days average is 28 So First 3 days Temperature is 3*28=84
Like Next 3 days is 3*31=93
Last day Temperature is =Total temperature-(First 3 days+Next 3 Days)
Last days is=210-(84+93) i.e 33
last day=x, (28+31+x)/3=30, solving x=317 years agoHelpfull: Yes(0) No(2)Let the no. of days be a,b,c,d,e,f,g
a+b+c+d+e+f+g/7=30
a+b+c/3=28
d+e+f/3=31
now from above a+b+c=84
and d+e+f=93
therefore g=210-84-93
g=33
so ans is 335 years agoHelpfull: for 7 day=7*30=210
for first three days=3*28=84
for next three days=31*3=93
total 6 days=84+93=177
i.e, for last day temp=210-177=33
ans3 years agoHelpfull: In given question we have temperature of hole week i.e 7 * 30,as well as we have remaining days of information.we need to find out the temperature of the last Day.let assume it as LD
7 * 30 = 3 * 28 + 3 * 31 + LD(Last Day)
LD = 7*30 - 3 1* 28 - 3 * 31
= 210 - 84 - 93
= 33.
Answer:
Calculate the average temperature from several temperature measurements using the formula:
Average temperature = sum of measured temperatures ÷ number of measurements
Where the sum of measured temperatures is found by adding up every measurement. Ensure that all of the measurements are in the same temperature unit before applying this formula. Convert from Celsius to Fahrenheit or vice-versa using the following expressions:
Temperature in Fahrenheit = (Temperature in Celsius × 1.8) + 32
Temperature in Celsius = (Temperature in Fahrenheit – 32) ÷ 1.8