In June, a runner ran a mile in 7:45. In September, the runner ran a mile in 5:51.
Find the percent of change from June to September. Round to the nearest hundredth of a percent.
what is this and how do you get it i need help quickly please anyoneeeeee!!!!!!
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Answer:
percentage change : 24.516%
Step-by-step explanation:
June mole : 7;46( min:sec)
September mile : 5:51
difference in timing : 7:45-5:51 = 1:54 (min:sec)
% change = difference in timing / original timing
= ( 1:54/7:45 ) x 100
changing everything into seconds
= ( 114 / 465 ) x 100%
= 24.516%
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