Question

In June, a runner ran a mile in 7:45. In September, the runner ran a mile in 5:51.


Find the percent of change from June to September. Round to the nearest hundredth of a percent.


what is this and how do you get it i need help quickly please anyoneeeeee!!!!!!

Answer 1

Answer:

percentage change : 24.516%

Step-by-step explanation:

June mole : 7;46( min:sec)

September mile : 5:51

difference in timing : 7:45-5:51 = 1:54 (min:sec)

% change = difference in timing / original timing

= ( 1:54/7:45 ) x 100

changing everything into seconds

= ( 114 / 465 ) x 100%

= 24.516%