Chemistry, asked by valueeducation5401, 11 months ago

In KJ/Mol, the heat evolved when 1mole of sulphuric acid react with sodium hydroxide is approximately

Answers

Answered by Anonymous
0

Answer:

114 kJ of heat.

Explanation:

Neutralization of a diprotic acid will produce more heat energy than a monoprotic acid.

○ Monoprotic acid + alkali

1 mole of HCl will react with 1 mole of NaOH to produce 57.0kJ of heat.

Diprotic acid + alkali1 mole of H2SO4 will react with 2 mole of NaOH to produce 114 kJ of heat.

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