In KJ/Mol, the heat evolved when 1mole of sulphuric acid react with sodium hydroxide is approximately
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Answer:
114 kJ of heat.
Explanation:
Neutralization of a diprotic acid will produce more heat energy than a monoprotic acid.
○ Monoprotic acid + alkali
1 mole of HCl will react with 1 mole of NaOH to produce 57.0kJ of heat.
○ Diprotic acid + alkali1 mole of H2SO4 will react with 2 mole of NaOH to produce 114 kJ of heat.
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