Question

In koushinks birthday party 1by
3 part of cake to distributed friends and 1by4 th path of cake to their parents Then how much cake was left.
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Answer 1

$Let \: size \:of \:the \: cake \:with \\Koushinks \: birthday \:party = x$

$Part \:of \: the \: cake \: distributed \: to \: friends \\= 1 \:by \: 3 \:part \:of \: the \:cake \\= \frac{x}{3}$

$Part \:of \: the \: cake \: distributed \: to \: parents \\= 1 \:by \: 4 \:part \:of \: the \:cake \\= \frac{x}{4}$

$\red{Portion \:of \: the \:cake \:left } \\= x - \frac{x}{3} - \frac{x}{4} \\= \frac{12x -4x-3x}{12} \\= \frac{12x-7x}{12} \\= \frac{5x}{12}$

Therefore.,

$\red{Portion \:of \: the \:cake \:left } \\\green {= \Big(\frac{5}{12}\Big)^{th} \: part \: of \:the \:cake }$

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Answer 2

Answer:

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