Question

In laboratory experiment 10 g potassium chlorate sample on decomposition gives following

data. The sample contain 3.8g of oxygen and the actual mass of oxygen in the quantity of

of potassium chlorate is 3.92g .calculate absolute error and relative error.​

Answer 1

Given info : In laboratory experiment 10 g potassium chlorate sample on decomposition gives following data. The sample contain 3.8g of oxygen and the actual mass of oxygen in the quantity of potassium chlorate is 3.92g .

To find : absolute error and relative error are ...

solution : absolute error is the difference between the actual value and calculated value.

here, the actual value = 3.92 g

the calculated value = 3.80 g

so absolute error = 3.92g - 3.80g = 0.12g

relative error is the ratio of absolute error to calculated value.

∴ relative error = absolute error/calculated value

= 0.12/3.80

= 0.0315789474 ≈ 0.032

Therefore the absolute error and the relative error are 0.12 g and 0.032 respectively.

Answer 2

Answer:

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