Question

in LIL
2. Certain force acting on a 20 kg mass changes its velocity from
5 ms-' to 2 m s- Calculate the work done by the force.​

Answer 1

Explanation:

Given

initial velocity = 5 ms-1

Final velocity = 2 ms-1

Work energy theorem

W =∆ K. E

W= 1/2 mv-2 1/2 mu-2

W= 1/2×20×2^2-1/2×20×5^2 ( Cancel both eq then you better understand )

W= 210 joules

Answer is 210 joules

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