Question

in ∆ LMN ,angle M =MN and angle M =130 degree .find angle L and angle N

please solve it​

Answer 1

Answer:

angle L = 25°

angle N = 25°

Step-by-step explanation:

Given that LM = MN

so this is an isosceles triangle

we know that angles opposite to equal sides are also equal

hence, LM = MN

also, angle N = angle L {eq.1}

Now,

angle M + angle + N + angle L = 180° (angle sum property of triangle)

130° + angle N + angle L = 180°

2(angle N) = 180° - 130°

angle N = (50/2)°

angle N = 25° ✔︎

From {eq.1} angle L = angle N

angle L = 25° ✔︎

Answer 2

Step-by-step explanation:

given that l m is equal to mn so this is an isosceles triangle we know that angles opposite to equal sides are also equal hence l m is equal to MM also angle and is equal to angle l now angle n + angle + n + angle is equal to 180 degrees (angle sum property of triangle )130 degree + angle and slotted angle is equal to 180 to bracket angle and bracket close is equal to 180 degree minus 130 angle and is equal to bracket 62 at back (close degrees angle and is equal to degree