In ∆LMN, if LM = 10cm, angle LNM = 90°, angle LMN = 30°, then NM=?
5√2cm
5cm
10√3cm
5√3cm
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LM=9cm
MN=12cm
LN=15cm
∴PM=4.5cm
QN=7.5cm
And we know that the line joining the mid points of the two sides of a triangle is parallel to the third side and is equal to half of it.
∴PQ= 1/2
MN=6cm
(i)Perimeter of trapezium MNQP=(4.5+7.5+12+6)
=24+6
=30cm
(ii)Area of trapezium= 1/2
×(sum of parallel sides)× (height)
=1/2×(12+6)×4.5
=9×4.5
=40.5cm.
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