Math, asked by sadiaperwaiz1901, 1 year ago

In ∆lmn,mn is extended to o.if angle mln=100-x,angel lmn =2x and angeleno=6x-5,find the value of x

Answers

Answered by bhagyashreechowdhury
3

If angle mln=100-x,angel lmn =2x and angle lno=6x-5, then the value of x is 21°.

Step-by-step explanation:

It is given,

∠mln = [100-x]

∠lmn = [2x]  

∠lno = [6x-5]

From the figure attached below we have  

∠lnm + ∠lno = 180° …… [strainght line]

⇒ ∠lnm = 180° - [6x - 5] = 180° - [6x - 5]

∠lnm = 180° - 6x + 5

Now, using the angle sum property in ∆lmn, we get

∠mln + ∠lmn + ∠lnm = 180°

⇒ [100-x] + [2x] + [180° - 6x + 5] = 180°  ..... [substituting the above values]

⇒ 5x = 100 + 5

⇒ x = 105/5

x = 21°

Thus, the value of x is 21°.

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