Question

in < ABC is exteri or angle of ∆ ABC,>B= 40,​

Answer 1

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Answer 2

Answer:

We are given m∠B=40 o

m∠A=70 o

Now,

BD

is a straight ray

so, m∠ACB+m∠ACD=180 o

→(1)

In △ABC,m∠A+m∠B+m∠ACB=180 o

→(2)

From (1) & (2)

m∠A+m∠B=m∠ACD

so, m∠ACD=40 o

+70 o

m∠ACD=110 o

Step-by-step explanation:

o this are degree dont forget it. ok

understand this ans