Question

In man brown eyes are dominant to blue and dark hair r dominant to red r .a man with brown eyes and red hair his farther was blue eyes marry a woman with blue eyes and dark hair whose mother was red haired they have 4 children. give the genotype and phenotype of all the parents and children

Answer 1

there are 4 genotypes and 4 phenotypes of children.

(I used B - Brown eyes(dominant)
b - blue eyes
D - Dark hair(dominant)
d - red hair

Now as man has brown eyes ,therefore there can be two possibilities either he has BB or Bb genotype...
as it is given that man's father has blue eyes (bb).. therefore the man must be having Bb genotype.
also, he has red hair thus, rr

therefore genotype if man = Bb rr

Similarly female has blue eyes (recessive) having bb genotype..
Female's mother was red haired(dd) and female is dark haired .... therefore possible genotype is Dd

therefore genotype of female = bb Dd

On crossing... Bb rr × bb Dd ... there are 4 possible genotypes..
Bb dd ( Brown eyed , red haired )
Bb Dd (Brown eyed ,Dark haired )
bb dd (blue eyed , red haired )
bb Dd (blue eyed ,Dark haired )

thus, 4 phenotypes and 4 genotypes.....

I hope it helps...! :))