In mass spectrograph the radius of semi circular path of the charged particle is proportional to ?
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ere, you have to use the Lorentz force equations. F = q ( v \mult B + E ) F=q(v\multB+E) . Since the magnetic force here is a variable (velocity varies due to the electric force), you will have to find the instantaneous force in the x and the y directions, which will give you a DE. This DE will be of the form d 2 x d t 2 = − ω 2 x d2xdt2=−ω2x , which represents SHM. After you do all this, you can finally find the velocity of the ion when it leaves the tube. You use that v in the expression
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