In mathematics test given to 10 students the following marks (out of 100) are
recorded: -
11, 09, 40, 37, 90, 40, 95, 55, 40, 65 find the mean, median and mode of this
data
Answers
Answer:
Mean = 48.2
Median = 40
Mode = 40
Step-by-step explanation:
Mean of the following data = 11+09+40+37+90+40+95+55+40+65 /10 = 48.2
Ascending order of the data = 9, 11, 37, 40, 40, 40, 55, 65, 90, 95.
Median of the data = 40+40 / 2 = 80/2 = 40
Mode of the data = 40
Hopefully
Brainliest
Step-by-step explanation:
Given:-
In mathematics test given to 10 students the following marks (out of 100) are
recorded: -
11, 09, 40, 37, 90, 40, 95, 55, 40, 65 .
To find:-
Find the mean, median and mode of this
data
Solution:-
Mean:-
Given observations are:
11, 09, 40, 37, 90, 40, 95, 55, 40, 65
Sum of all observations
= 11+9+40+37+90+40+95+55+40+65
=482
Number of all observations = 10
We know that
Mean = Sum of all observations/Number of all observations
=> Mean = 482/10
Mean = 48.2
Median :-
Given observations are:
11, 09, 40, 37, 90, 40, 95, 55, 40, 65
On writing them into ascending order
09, 11 , 37 , 40, 40, 40, 55 ,65 , 90 , 95
Number of all observations = 10
It is an even number
We know that
The number of observations is n an even number then median is the average of the (n/2)th and
(n/2)+1 th observations
n/2 th observation
=> 10/2
= 5th observation = 40
6th observation = 40
Median = (40+40)/2
Median = 80/2
Median = 40
Mode :-
Given observations are:
11, 09, 40, 37, 90, 40, 95, 55, 40, 65
On writing them into ascending order
09, 11 , 37 , 40, 40, 40, 55 ,65 , 90 , 95
Most occuring observation = 40
40 occurs 3 times
Mode = 40
Answer:-
1)Mean = 48.2
2)Median = 40
3)Mode = 40
Used formulae:-
- Mean = Sum of all observations/Number of all observations
- The number of observations is n an even number then median is the average of the (n/2)th and
- (n/2)+1 th observations
- Mode is the most frequent occuring observation of the given data.