Question

In maths give me answer to these 2 questions ​

Answer 1

Answer:

I hope you will understand

Answer 2

(c) $(3^8 ÷ 3^4) \times 3^2$

= $({3}^{8-4}) \times 3^2$

(∵ $a^m ÷ a^n = a^{m-n}$)

= ${3}^{8-4+2}$

(∵ $a^m \times a^n = {a}^{m+n}$)

= $3^6$ or $729$.

(d) $(5^{20} \times 5^{12}) ÷ 5^3$

Using the above formulae,

= $5^{20 + 12 - 3}$

= $5^{29}$.

More:-

1. $a^{-n} = \frac{1}{a^n}$
2. $\sqrt[m]{a^n} = a^{\frac{n}{m}}$
3. $x^0 = 1$ (if x ≠ 0).