Biology, asked by alibilal1988, 3 days ago

In Mendel's "Experiment 1," true-breeding pea plants with spherical seeds were crossed with true-breeding plants with dented seeds. (Spherical seeds are the dominant characteristic.) Mendel collected the seeds from this cross, grew F1-generation plants, let them self-pollinate to form a second generation, and analysed the seeds of the resulting F2 generation. The results that he obtained, and that you would predict for this experiment are:
A. ▁(1/2) the F1 and ¾ of the F2 generation seeds were spherical.
B. ½ the F1 and 1/4 of the F2 generation seeds were dented.
C. All the F1 and ¾ of the F2 generation seeds were spherical.
D. 3 / 4 of the F1 and 9 / 16 of the F2 generation seeds were spherical.

Answers

Answered by qaiedshowketbhatt
0

Explanation:

In Mendel's "Experiment 1," true-breeding pea plants with spherical seeds were crossed with true-breeding plants with dented seeds. (Spherical seeds are the dominant characteristic.) Mendel collected the seeds from this cross, grew F1-generation plants, let them self-pollinate to form a second generation, and analyzed the seeds of the resulting F2 generation. The results that he obtained, and that you would predict for this experiment are:

Tutorial

F1-generation plants

Mendel crossed SS (spherical seeds) with ss (dented seeds.)

All of the gametes of the spherical seeded parent have the S (dominant) allele and all of the gametes of the dented seeded parent have the s (recessive) allele. All of the F1 generation plants will have the genotype of Ss (heterozygous), and all will be spherical seeded.

F1 generation

=

F2-generation plants

Mendel let the F1-generation plants self-pollinate to form a second generation and he analyzed the seeds of the resulting F2 generation.

F2 generation

=

All F1-hybrid plants have the genotype Ss and all are spherical (dominant characteristic). The recessive alleles segregate during gamete formation. As a result, one out of four possible combinations of F2-generation plants will have the homozygous recessive genotype (ss).

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Answered by chandan454380
0

Answer:

the answer is C. All the F1 and 3/4 of the F2 generation seeds were spherical

Explanation:

Mendel crossed true breeding pea plant with spherical seeds with true breeding pea plant with dented seeds.

we are taking S allele to denote spherical seeds

and s allele to denote dented seeds.

S allele is dominant over s allele. Therefore in heterozygous condition, Ss the phenotype will be spherical and in homozygous condition, ss will show dented phenotype and SS will show spherical phenotype.

Now as we can see in diagram of F1 generation we have crossed true breeding spherical seeds with genotype SS taken as male and true breeding dented seeds with ss genotype taken as female.

After crossing them in Punnett square we can see that all the plants have spherical seeds with

Ss genotype i.e. they are heterozygous dominant.

Now on self crossing Ss allele Punnett square taking one as male and one as female that

 \frac{3}{4}

of them are with spherical seeds having genotype as SS,Ss

and

 \frac{1}{4} th

of them are with dented seeds having genotype as ss.

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