Chemistry, asked by mathangi2005nv, 9 months ago

In Mendeleev’s periodic table, iodine with lower atomic weight than that of tellurium was placed along with a) iron, cobalt and nickel b) fluorine, chlorine and bromine c) oxygen, sulphur and selenium d) carbon, silicon and germanium

Answers

Answered by Mahimalhotra
5

Answer:

The correct one is option b

Answered by mithun890
0

Mendeleev's periodic table

Explanation:

  • In Mendeleev’s periodic table, iodine with lower atomic weight than that of tellurium was placed along with fluorine, chlorine and bromine.
  • Mendeleev arranged elements in a table in horizontal rows and vertical columns in order of increasing atomic weights. So that the elements with similar properties occupied the same vertical group or column.
  • He recognized the importance of periodicity and classified the elements using physical and chemical properties.
  • He noticed that some of the elements would not fit into his classification method if the order of atomic weight was followed. He ignored the order of atomic weights, assuming that the atomic measurements were incorrect, and grouped elements with similar properties.
  • Because of similarities in properties, iodine with a lower atomic weight than tellurium (Group VI) was positioned in Group VII with fluorine, chlorine, and bromine.
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