In metal oxide, the oxide ions are arranged on corners as well as on all face centres while metal cation occupy 12.5% tetrahedral voids and 50% octahedral voids. The formula of metal oxide is
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Here's your answer
M3O4 Z=4 so no. of oxide is 4.
No. of metal =Total no. of otacahedral voids is 4 and 50% is filed + Total no. of tetrahedral voids is 8 and 12.5% is filled
= 4×1/2 + 8×1/8 =3
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