In meterbridge the null point is found to be 60 cm from a with x and y as shown when the resistance of 15 ohm is connected with series with y, the null point is formed to be shift by 10 cm towards the end a of the wire find the position of null point if the resistance of 30 ohm with connected in parallel with resistance y ,.....
Answers
Answer:
the position of null point if the resistance of 30 ohm with connected in parallel with resistance y is 75 cm from end A.
Explanation:
In meterbridge the null point is found to be 60 cm from a with x and y as shown when the resistance of 15 ohm is connected with series with y, the null point is formed to be shift by 10 cm towards the end a of the wire.
Now, X/Y= 60r/(100-60r) [ r= resistance per cm]........(1)
= 3/2
Now, the resistance of 15 ohm is connected with series with y,
X/Y+15= 50r/(100-50r)
= 1
X= Y+15.........(2)
Now, putting the value of X in (1)
Y+15/Y= 3/2
3Y=2Y+30
Y= 30 ohm
Now putting the value of Y in (2)
X= 45 ohm
the resistance of 30 ohm with connected in parallel with resistance y the new value of resistance between B and C is Y'
Y'= 30x30/30+30
= 15 ohm
Let null point is at a distance of l cm
X/Y'=lr/(100-l)r
45/15= l/(100-l)
3 =l/(100-l)
4l= 300
l = 75 cm
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