in metre bridge if we connect 12ohms in a left gap and x ohms in a right gap and they null deflection point is found at to be at 32cm from the left . Find the value of x. If we interchange the given resistance.Calculate the strand of null deflection point from the right.
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Answer:
X = 24 ohm
new null point , l = 66.6 cm
Explanation:
X/68 = 12/32
X= 68*12/32=24 ohm
if the resistances are interchanged,
X/l = 12 / 100-l
24/12 = l/100-l
2(100-l)= l
200=3l
l=200/3
l= 66.6 ohm
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