In △MGN, MP⊥GN. If MG=a units, MN=b units, GP=c units and PN=d units.
Prove that (a+b)(a−b)=(c+d)(c−d).
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Explanation:
In ΔGMP,
Use Pythagoras Theorem,
a
2
=(MP)
2
+c
2
⟹a
2
−c
2
=(MP)
2
In ΔMNP,
Use Pythagoras Theorem,
b
2
=(MP)
2
+d
2
⟹b
2
−d
2
=(MP)
2
Equating both,
a
2
−c
2
=b
2
−d
2
⟹a
2
−b
2
=c
2
−d
2
⟹(a−b)(a+b)=(c−d)(c+d)
⟹
(c−d)
(a−b)
=
(a+b)
(c+d)
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