In mice, the ability to run normally is a dominant trait. Mice with this trait are called running mice
(R). The recessive trait causes mice to run in circles only. Mice with this trait are called waltzing
mice (r). Hair color is also inherited in mice. Black hair (B) is dominant over brown hair (b). Cross a
heterozygous running and black mouse with a heterozygous running, brown mouse. What is the
probability of waltzing a brown mouse?
Answers
Answer:
zero
Explanation:
let cross between RrBB and Rrbb
RrBB - heterozygous running black mouse
Rrbb - heterozygous running brown mouse
Answer:
Probability of waltzing a brown mouse is approximately 68%.
Explanation:
To solve this problem, we can use the principles of Mendelian genetics and Punnett squares.
First, let's identify the genotypes of the parent mice:
Heterozygous running, black mouse: RrBb
Heterozygous running, brown mouse: Rrbb
To create a Punnett square, we'll write the possible gametes (sperm and egg cells) for each parent along the top and left sides of a grid:
| R r
B | RB rB
b | Rb rb
Then, we'll combine each possible gamete from the male parent with each possible gamete from the female parent and write the resulting genotype of the offspring in the corresponding box:
| R r
--|--------
B | RRBB RrBb
B | RrBb rrbb
Now we can count the number of offspring with the waltzing, brown phenotype (rrbb) and calculate the probability:
There is only one box out of four that corresponds to an rrbb offspring, so there is a chance of any individual offspring having this phenotype.
To find the probability of at least one offspring having this phenotype, we can use the complement rule: the probability of no offspring having the phenotype is , so the probability of at least one offspring having the phenotype is , which is approximately 0.68 or 68%.
Therefore, the probability of obtaining at least one waltzing, brown mouse from a cross between a heterozygous running, black mouse and a heterozygous running, brown mouse is approximately 68%.
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