Question

In Michelson interferometer 200 fringes cross the field of view when the movable mirror is moved through distance of 0.0589 mm. The wavelength of light used?


Option 1:
5790 Å

Option 2:
5690 Å



Option 3:
5890 Å

Option 4:
5990 Å

Answer 1

Answer:

2

Explanation:

idk it's just a guess sjsjsksks

Answer 2

The wavelength of the light used is  5890 Å.

Given:

No. of fringes that cross through the field, m = 200

Distance, d = 0.0589 mm = 589 x $10^{-7}$ m

To find:

The wavelength of light used (n).

Solution:

Formula:  $d = \frac{m.n}{2}$

Therefore, $n = \frac{2d}{m}$

Substituting the values of d and m, we get,

⇒ $n = \frac{(2)(589)(10^{-7 )} }{200}$

⇒ n = 589 x $10^{-9} m$

⇒ n = 5890 x $10^{-10} m$

⇒ n = 5890 Å .