In millikan's oil drop experiment the charge of three oil drops are 2,0.04 and 0.8 respectively. What could be the probable charge of electron and the number of electron attached to drop?
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charge of an electron is always constant and is 1.6×10^-19 coulomb
in my book its given that final expression of Milliken experiment is q=ne
so,no. of electrons in 1st drop is
n=q/e =2/1.6×10^-19
=1.2×10^19 electrons
for 2nd drop
n=0.04/1.6×10^-19
=0.025×10^19 electrons
for 3rd drop
n=0.8/1.6×10^-19
=.5×10^19 electrons
in my book its given that final expression of Milliken experiment is q=ne
so,no. of electrons in 1st drop is
n=q/e =2/1.6×10^-19
=1.2×10^19 electrons
for 2nd drop
n=0.04/1.6×10^-19
=0.025×10^19 electrons
for 3rd drop
n=0.8/1.6×10^-19
=.5×10^19 electrons
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