in morning walk three persons step off together their steps measures 80cm 85 am and 90 cm respectively what is the minimum distance each should walk so that he can cover the distance together at the earliest?
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minimum distance should be equal to LCM of 80,85,90.
= 80 = 2 . 2 . 2 . 2 . 5 = 2^4 . 5
= 85 = 17 . 5
= 90 = 3 . 3 . 2 . 5 = 3^2 . 2 . 5
Therefore the LCM of (80,85,90) = 5 . 2^4 . 3^2 . 17
= 12240 CM or = 122.40m
= 80 = 2 . 2 . 2 . 2 . 5 = 2^4 . 5
= 85 = 17 . 5
= 90 = 3 . 3 . 2 . 5 = 3^2 . 2 . 5
Therefore the LCM of (80,85,90) = 5 . 2^4 . 3^2 . 17
= 12240 CM or = 122.40m
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