Physics, asked by ankitathakur1604, 8 months ago

in motion, its acceleration is determined by the applied force and kinetic friction between the
VAATA
Friction and Dynamics of Circular Motion
Kinetic friction, F = \.R=, mg = 0.5 x 3 x 10 = 15 N
According to Newton's second law, the acceleration a of the box is given by :
Note that role of limiting friction is only confined to set the body moving. Once the body is
, = R
Net force 5
=-=1.67 ms?
Mass 3
403
Net force = F - F = 20 – 15 = 5 N
urfaces in contact.
Example 11.1. A block of 10 kg is pulled at a constant speed on a rough horizontal
urface by a force of 20 N. Find the co-efficient of kinetic friction. Given that g = 10 ms?​

Answers

Answered by shravan7294
0

correct answer is 20..........

Answered by rishitasenwal
0

Answer:

I am sorry but I am in class 8

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