Physics, asked by sudhanvamesuja123, 1 year ago

In Mrs. Pinto’s flat there are 6 bulbs of 100 W each, a heater of 2 kW and 5 fans of 50W each. If these are used everyday as shown below, calculate the cost of energy consumption for a month of 30 days at the rate of Rs.3.50 per kW h. 6 bulbs of 100 W each used 8 h per day 1 heater of 2 kW used half hour daily 5 fans of 50 W each are used 6 h everyday.

Answers

Answered by arenarohith
60

Answer:

Energy consumed by bulbs in one month = 6*100*8*30 / 1000 = 144 kWh

Energy consumed by heater in one month = 1*2*0.5*30 = 30 kWh

Energy consumed by fans in one month = 5*50*6*30 / 1000 = 45 kWh  

Total Energy consumed = ( 144 + 30 + 45 ) kWh = 219 kWh

HOPE..IT..HELPS..!!

Answered by subhrajeet57
3

Answer:

then

cost=219 ×3.50

=766.50 rupees

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